/22 Subnet Calculator

A /22 subnet mask (255.255.252.0) is a widely deployed supernet allocation across enterprise corporate campuses, educational institutions, hospital ne

Networking

Formula & Methodology

ext{Subnet Mask} = 255.255.252.0 quad ( ext{Prefix } /22) ext{Host Bits} = 32 - 22 = 10 ext{Total Addresses} = 2^{10} = 1,024 ext{Usable Hosts} = 1,024 - 2 = 1,022 ext{Component /24 Blocks} = 2^{24 - 22} = 4 ext{ subnets}

A /22 prefix allocates 22 bits for the network and reserves 10 bits for host addressing. Ten host bits provide 2¹⁰ = 1,024 total IP addresses. Subtracting the initial network identifier and trailing broadcast address leaves 1,022 usable client hosts. In terms of legacy Class C networks, a /22 represents exactly four aggregated /24 subnets (4 × 256 = 1,024).

Enterprise Block Details for 172.16.0.0/22

1,022 Usable Hosts (1,024 Total IPs)

Overview

A /22 subnet mask (255.255.252.0) is a widely deployed supernet allocation across enterprise corporate campuses, educational institutions, hospital networks, and cloud VPC environments. The /22 Subnet Calculator computes the complete 1,024-address block, outlining the 1,022 usable host IPs, network and broadcast addresses, and the 4 contiguous /24 subnets that comprise the supernet.

Deploying a /22 allows organizations to either maintain a large unified broadcast domain for dynamic DHCP pooling or cleanly divide the address space into four distinct /24 departments (such as Executive, Engineering, Guest Wi-Fi, and IoT). This tool streamlines enterprise capacity planning and route summarization.

Worked Examples

Example 1: Corporate Campus Network (172.16.0.0/22)

Base IP = 172.16.0.0, Prefix = /22 (255.255.252.0)

Network ID: 172.16.0.0.
Wildcard mask: 0.0.3.255.
Broadcast address: 172.16.3.255.
Usable host range: 172.16.0.1 through 172.16.3.254.
Total usable capacity: 1,022 hosts.

Final Answer: 1,022 Usable Hosts (172.16.0.1 - 172.16.3.254)

Example 2: Dividing a /22 into Four /24 Departmental VLANs

Base IP = 10.50.4.0/22

VLAN 10 (Admin): 10.50.4.0/24 (254 hosts).
VLAN 20 (Staff): 10.50.5.0/24 (254 hosts).
VLAN 30 (VoIP): 10.50.6.0/24 (254 hosts).
VLAN 40 (IoT): 10.50.7.0/24 (254 hosts).
Summarized upstream route: 10.50.4.0/22.

Final Answer: 4 Subnets: 10.50.4.0/24, .5.0/24, .6.0/24, .7.0/24

Example 3: Next Adjacent /22 Block Progression

Base block = 192.168.0.0/22

Current block covers third octets 0, 1, 2, 3 (192.168.0.0 to 192.168.3.255).
Next block starts at third octet 4: 192.168.4.0/22.

Final Answer: Next Block: 192.168.4.0/22

Reference Table

Subnet Block	Network Address	Usable Host Range	Broadcast Address	Usable Hosts
Subnet 1 (/24)	x.x.0.0	x.x.0.1 - x.x.0.254	x.x.0.255	254
Subnet 2 (/24)	x.x.1.0	x.x.1.1 - x.x.1.254	x.x.1.255	254
Subnet 3 (/24)	x.x.2.0	x.x.2.1 - x.x.2.254	x.x.2.255	254
Subnet 4 (/24)	x.x.3.0	x.x.3.1 - x.x.3.254	x.x.3.255	254
Combined /22	x.x.0.0	x.x.0.1 - x.x.3.254	x.x.3.255	1,022

Frequently Asked Questions

What is the dotted decimal subnet mask for a /22 prefix?

The subnet mask for /22 is 255.255.252.0.

What numbers can the third octet start with in a /22 subnet?

In a /22 subnet, the third octet increases in multiples of 4: 0, 4, 8, 12, 16, 20, 24, 28, 32, ..., 248, 252.

What is the wildcard mask for a /22 network?

The wildcard mask is 0.0.3.255.

Is a single /22 broadcast domain too large for Wi-Fi networks?

Large single broadcast domains with 1,000+ wireless clients can experience broadcast storm degradation. Best practice is to segment the /22 into separate /24 VLANs for wired, wireless, and voice traffic.

How many Class C networks are contained in a /22?

A /22 supernet contains exactly 4 consecutive Class C (/24) networks.